Two waves, each of amplitude 1.5 mm and frequency 10 Hz, are travelling in opposite direction with a speed of 20 mm/s. The distance in mm between-adjacent nodes is

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Q: 29 (CDS-I/2004)
Two waves, each of amplitude
1.5 mm and frequency 10 Hz, are travelling in opposite direction with a speed of 20 mm/s. The distance in mm between-adjacent nodes is

question_subject: 

Science

question_exam: 

CDS-I

stats: 

0,7,3,0,7,3,0

keywords: 

{'waves': [0, 0, 3, 0], 'amplitude': [1, 0, 7, 8], 'adjacent nodes': [0, 0, 1, 0], 'hz': [0, 0, 4, 8], 'distance': [0, 3, 3, 3], 'opposite direction': [0, 0, 1, 2], 'speed': [0, 1, 2, 0]}

The distance between adjacent nodes in a wave is equal to half the wavelength. To calculate the wavelength, we can use the formula:

wavelength = wave speed / frequency

In this question, given that the wave speed is 20 mm/s and the frequency is 10 Hz, we can substitute these values into the formula:

wavelength = 20 mm/s / 10 Hz = 2 mm

Therefore, the wavelength of the wave is 2 mm. Since the distance between adjacent nodes is equal to half the wavelength, the distance between adjacent nodes is:

2 mm / 2 = 1 mm

So, the correct answer is option 2, which states that the distance between adjacent nodes is 1.0 mm.

Alert - correct answer should be option 4: 2.0.