Two men are standing on opposite ends of a bridge of 1200 metres long. If they walk towards each other at the rate of 5 m/minute and 10 m/ minute respectively, in how much time will they meet each other?

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Submitted by examrobotsa on

Q: 108 (CDS-I/2004)
Two men are standing on opposite ends of a bridge of 1200 metres long. If they walk towards each other at the rate of 5 m/minute and 10 m/ minute respectively, in how much time will they meet each other?

question_subject: 

Maths

question_exam: 

CDS-I

stats: 

0,22,13,9,22,3,1

keywords: 

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In this question, we are given that two men are standing on opposite ends of a bridge that is 1200 meters long. They start walking towards each other at different rates.

To find out how much time it takes for them to meet, we need to calculate the total distance they need to cover by adding their individual distances.

The first man is walking at a rate of 5 m/minute, so he will cover a distance of 5m every minute. The second man is walking at a rate of 10 m/minute, so he will cover a distance of 10m every minute.

Since they are walking towards each other, the sum of their individual distances will give us the total distance they need to cover.

Therefore, the total distance they need to cover is (5m/minute + 10m/minute) = 15m/minute.

To find out the time it takes for them to meet, we divide the total distance (1200m) by the rate at which they are covering the distance (15m/minute).

Therefore, the answer is obtained by dividing 1200m by 15m/minute.

1200m / 15m/minute = 80 minutes.

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