In this question, we have a converging lens with a focal length of 25 cm and a luminous object placed at a distance of 40 cm from the lens. We need to determine the nature of the image formed on the screen.

To solve this problem, we can use the lens formula:

1/f = 1/v - 1/u

where f is the focal length of the lens, v is the distance of the image from the lens, and u is the distance of the object from the lens.

Given that f = 25 cm and u = -40 cm (negative because the object is on the left side of the lens), we can substitute these values into the lens formula and solve for v:

1/25 = 1/v + 1/40

(40 + 25)/25v = 1

65/25v = 1

v = 25/65 = 5/13 cm

Since the image distance v is positive, it is on the opposite side of the lens from the object, which means the image is real. Moreover, the positive sign indicates that the image is inverted.

Finally, the magnification of the image can be calculated using the magnification formula:

m = -v/u =