If the absolute refractive indices of glass and water are 3/2 and 4/3 respectively, what will be the ratio of velocity of light in glass and water ?

examrobotsa's picture

Submitted by examrobotsa on

Q: 92 (NDA-I/2017)
If the absolute refractive indices of glass and water are 3/2 and 4/3 respectively, what will be the ratio of velocity of light in glass and water ?

question_subject: 

Science

question_exam: 

NDA-I

stats: 

0,5,3,2,0,1,5

keywords: 

{'velocity': [0, 2, 2, 6], 'absolute refractive indices': [0, 0, 0, 1], 'ratio': [1, 0, 1, 12], 'glass': [0, 0, 1, 4], 'light': [16, 4, 34, 62]}

This question is asking for the ratio of velocity of light in glass and water, given their respective absolute refractive indices.

The absolute refractive index (n) of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in that medium. So, the absolute refractive index of glass (n1) can be given as n1 = 3/2 and the absolute refractive index of water (n2) can be given as n2 = 4/3.

The velocity of light in a medium can be calculated by dividing the speed of light in vacuum (c) by the absolute refractive index (n) of the medium. Thus, the velocity of light in glass (v1) can be calculated as v1 = c/n1 and the velocity of light in water (v2) can be calculated as v2 = c/n2.

To find the ratio of v1 to v2, we can divide v1 by v2: (v1/v2) = (c/n1)/(c/n2) = n2/n1.

Plugging in the given values, we have (4/3) / (3/2) = (4/3) * (2/3