At a given time, two players are standing on a play-field. The cartesian coordinates of their locations are (20, 60) and (-40, -20) units. What is the distance between the players ?

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Submitted by examrobotsa on

Q: 148 (IAS/1999)
At a given time, two players are standing on a play-field. The cartesian coordinates of their locations are (20, 60) and (-40, -20) units. What is the distance between the players ?

question_subject: 

Maths

question_exam: 

IAS

stats: 

0,3,1,0,1,3,0

keywords: 

{'distance': [0, 3, 3, 3], 'cartesian coordinates': [0, 1, 0, 0], 'play': [0, 2, 0, 0], 'players': [0, 1, 4, 2], 'field': [1, 1, 4, 8], 'units': [1, 2, 4, 7]}

To find the distance between two points in a Cartesian coordinate system, we can use the distance formula:

Distance = ?((x2 - x1)^2 + (y2 - y1)^2)

Using the given coordinates:

Player 1: (20, 60)

Player 2: (-40, -20)

Distance = ?((-40 - 20)^2 + (-20 - 60)^2)

= ?((-60)^2 + (-80)^2)

= ?(3600 + 6400)

= ?10000

= 100 units

Therefore, the distance between the players is 100 units.